A divide by 490 counter requires how many flip flops?
A divide by 490 counter requires how many flip flops?
Right Answer is:
9
SOLUTION
- Modulus of a Counter: The modulus of a counter is the number of states it can count before it resets to its initial state.
- Flip-Flops: These are basic digital circuits that can store one bit of information.
To determine the minimum number of flip-flops required, we need to find the smallest integer ‘n’ such that:
2n >= 490
By calculating powers of 2, we find that:
- 28 = 256
- 29 = 512
Since 512 is the smallest power of 2 greater than 490, we need 9 flip-flops to design a divide-by-490 counter.