A shunt generator delivers 100A at 200V. Find the generated voltage if shunt field resistance and armature resistance are 50 Ω and 0.1Ω respectively.
A shunt generator delivers 100A at 200V. Find the generated voltage if shunt field resistance and armature resistance are 50 Ω and 0.1Ω respectively.
Right Answer is:
210.4 V
SOLUTION
Given Information:
- Load current (IL) = 100 A
- Terminal voltage (Vt) = 200 V
- Shunt field resistance (Rsh) = 50 Ω
- Armature resistance (Ra) = 0.1 Ω
Step-by-Step Solution:
- Calculate Shunt Field Current (Ish):
-
- The shunt field current flows through the shunt field resistance.
- Using Ohm’s law:
- Ish = Vt / Rsh
- Ish = 200 V / 50 Ω = 4 A
2. Calculate Armature Current (Ia):
- The armature current is the sum of the load current and the shunt field current.
- Ia = IL + Ish
- Ia = 100 A + 4 A = 104 A
3. Calculate Voltage Drop Across Armature Resistance (Va):
- Using Ohm’s law:
- Va = Ia * Ra
- Va = 104 A * 0.1 Ω = 10.4 V
4. Calculate Generated EMF (Eg):
- The generated EMF is the sum of the terminal voltage and the voltage drop across the armature resistance.
- Eg = Vt + Va
- Eg = 200 V + 10.4 V = 210.4 V
Therefore, the generated voltage (Eg) is 210.4 volts.