Find the probability that there are 53 Sundays in a non-leap year
Find the probability that there are 53 Sundays in a non-leap year
Right Answer is:
1/7
SOLUTION
A non-leap year has 365 days. Dividing 365 by 7 (days in a week), we get 52 weeks and 1 extra day.
Possible Outcomes for the Extra Day:
This extra day can be any of the 7 days of the week: Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, or Saturday.
Favorable Outcome:
For a non-leap year to have 53 Sundays, the extra day must be a Sunday.
Calculating Probability:
- Total Possible Outcomes: 7 (any day of the week)
- Favorable Outcome: 1 (Sunday)
Probability = Favorable Outcomes / Total Possible Outcomes
Therefore, the probability of having 53 Sundays in a non-leap year is:
Probability = 1/7