Find the probability that there are 53 Sundays in a non-leap year

Find the probability that there are 53 Sundays in a non-leap year

Right Answer is:

1/7

SOLUTION

A non-leap year has 365 days. Dividing 365 by 7 (days in a week), we get 52 weeks and 1 extra day.

Possible Outcomes for the Extra Day:

This extra day can be any of the 7 days of the week: Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, or Saturday.

Favorable Outcome:

For a non-leap year to have 53 Sundays, the extra day must be a Sunday.

Calculating Probability:

  • Total Possible Outcomes: 7 (any day of the week)
  • Favorable Outcome: 1 (Sunday)

Probability = Favorable Outcomes / Total Possible Outcomes

Therefore, the probability of having 53 Sundays in a non-leap year is:

Probability = 1/7

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