Answer:
"1/√5
"To determine the new power factor of an RL circuit when the frequency is doubled, we can follow these steps:
Given Information
Initial power factor $ cos phi = frac{1}{sqrt{2}}$
Step 1: Understanding the Power Factor
The power factor for an RL circuit is given by:
$cos phi = frac{R}{Z}$
where:
R is the resistance,
Z is the impedance.
The impedance Z for an RL circuit is given by:
$Z = sqrt{R^2 + (X_L)^2}$
where XL is the inductive reactance, which is defined as:
XL = ωL
ω = 2πf
where f is the frequency
Step 2: Initial Conditions
From the initial power factor:
$cos phi = frac{R}{Z} = frac{1}{sqrt{2}}$
This implies that:
Z = R √2
Using the impedance formula:
$Z^2 = R^2 + (X_L)^2$
Substituting for Z :
$(R sqrt{2})^2 = R^2 + (X_L)^2$
$2R^2 = R^2 + (X_L)^2$
$(X_L)^2 = R^2$
Thus, we find that:
XL = R
Step 3: Doubling the Frequency
When the frequency is doubled, the new inductive reactance XL = R becomes:
$X_L’ = 2X_L = 2R$
Step 4: New Impedance Calculation
Now, we calculate the new impedance Z’:
$Z’ = sqrt{R^2 + (X_L’)^2} = sqrt{R^2 + (2R)^2} = sqrt{R^2 + 4R^2} = sqrt{5R^2} = Rsqrt{5}$
Step 5: New Power Factor Calculation
Now we can find the new power factor $cos phi’$:
$cos phi’ = frac{R}{Z’} = frac{R}{Rsqrt{5}} = frac{1}{sqrt{5}}$
Conclusion
Thus, when the frequency is doubled, the new power factor of the RL circuit becomes:
$frac{1}{sqrt{5}}$